5272道题目5525 条题源记录 · 相同内容已合并
二次方程・零点与韦达定理挑战
The solutions to \( x^2+6x+6=0 \) are r and s, where \( r<s \). The solutions to \( x^2+10x+13=0 \) are t and u, where \( t<u \). The solutions to \( x^2+16x+c=0 \), where c is a constant, are \( r+u \) and \( s+t \). What is the value of c?
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二次方程・零点与韦达定理进阶
\( \left(2x-4\right)\left(x-8\right)\left(x-9\right)=0 \)
What is the sum of the solutions to the equation?
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二次方程・零点与韦达定理进阶
\( y=-8x+26 \)
\( y=2x^2+16 \)
The graphs of the equations in the given system of equations intersect at the point \( \left(a,\ b\right) \) in the xy-plane. What is a possible value of \( a \)?
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二次方程・零点与韦达定理挑战
\( 9x^2+30x+q=43 \)
In the given equation, \( q \) is a constant. One solution to the given equation is \( \frac{-5+\sqrt{14}}{3} \). What is the value of \( q \)?
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二次方程・零点与韦达定理进阶
\( x^2-2=23 \)
Which value is a solution to the given equation?
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二次方程・零点与韦达定理挑战
\( f\left(x\right)=\left(x-a\right)\left(x-b\right) \)
The function \( f \) is defined by the given equation, where a and b are integer constants. If \( f(32)>0 \), \( f(35)<0 \), and \( f(38)>0 \), which of the following could be the value of \( a+b \)?
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二次方程・零点与韦达定理挑战
\( x^2-11x-3=0 \)
What is a solution to the given equation?
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二次方程・零点与韦达定理进阶
\( x^2+y=21 \)
\( -x+y=1 \)
The solutions to the given system of equations are of the form (x, y). What is a possible value of x ?
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二次方程・零点与韦达定理挑战
\( w^2+8w-28=0 \)
Which of the following is a solution to the given equation?
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二次方程・零点与韦达定理进阶
\( x(x-13)(x+6)(x-5)^2=0 \)
What is the greatest solution to the given equation?
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二次方程・零点与韦达定理进阶
\( y-x=47 \)
\( y=x^2-45x \)
The graphs of the equations in the given system intersect at the point (\( x \), \( y \)) in the xy-plane. What is a possible value of \( y \)?
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二次方程・零点与韦达定理进阶
\( 12(w-a)(w+8)=4(w+8) \)
In the given equation, \( a \) is a constant. The sum of the solution is \( \frac{34}{3} \). What is the value of \( a \)?
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