找到你今天要练的题。

\( g\left(x\right)=\frac{3}{5}x+\frac{7}{6} \) 
\( h\left(x\right)=6x-5 \) 
The functions g and h are defined by the equations shown. Which expression is equivalent to g(x) · h(x )?

Which expression is equivalent to 6x⁸y²+12x²y²?

 Which expression is equivalent to 9x²+5x ?

The expression 4x² + bx − 45, where b is a constant, can be rewritten as (hx + k)( x + j ), where h, k, and j are integer constants. Which of the following must   be an integer?

\( x^2-5x-1=0 \) 
What is the sum of the solutions to the given equation?

\( x^2+9x+5=0 \) 
One solution to the given equation can be written as \( x=\frac{-9+\sqrt{k}}{2} \) , where \( k \)  is a constant. What is the value of ?

f (x)=(x-a)(x-b)
The function f is defined by the given equation, where a and b are integer constants. If  f (35)>0 ,  f (38)<0, and f (41)>0 , which of the following could be the value of a+b?

\( 6x^2\left(3x-16\right)\left(3x-u\right)=0 \) 
In the given equation, u is a positive constant. The sum of the solution to the equation is 13. What is the value of u?

(x - 21)²= 1
What is the sum of the solutions to the given equation?

56x² +(56s ＋r )x＋rs =0
ln the given equation, r and s are positive constants. The product of the solutions to the given equation is krs, where k is a constant. What is the value of k?

\( 46x^2+\left(46s+r\right)x+rs=0 \) 
In the given equation, r and s are positive constants. The product of the solutions to the given equation is krs, where k is a constant. What is the value of k?

46x²+(46s ＋r)x ＋rs =0
In the given equation, r and s are positive constants. The product of the solutions to the given equation is krs, where k is a constant. What is the value of k?