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二次方程・零点与韦达定理挑战

y = x² + 2x + 1
x + y + 1 = 0
If (x₁ , y₁) and (x₂ , y₂) are the two solutions to the system of equations above, what is the value of y₁ + y₂?

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二次方程・零点与韦达定理挑战

8x + y = -11
2x² = y + 341
The graphs of the equations in the given system of equations intersect at the point (x , y ) in the xy-plane. What is a possible value of x ?

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二次方程・零点与韦达定理挑战

x(x + 1) -56 = 4x(x -7)
What is the sum of the solutions to the given equation?

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二次方程・零点与韦达定理挑战

x² -2x -9 = 0
One solution to the given equation can be written as \( 1+\sqrt{k} \) , where k is a constant. What is the value of k ?

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二次方程・零点与韦达定理挑战

x -29 = (x - a )(x - 29)
Which of the following are solutions to the given equation, where is a constant and a > 30 ?
I.a
II.a + 1
III.29

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二次方程・零点与韦达定理挑战

In the xy-plane, the graph of y = 3x²- 14x intersects the graph of y = x at the points (0 , 0) and (a , a). What is the value of a ?

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二次方程・零点与韦达定理挑战

64x² -(16a + 4b)x + ab = 0
In the given equation, a and b are positive constants. The sum of the solutions to the given equation is k(4a + b), where k is a constant. What is the value of k ?

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二次方程・零点与韦达定理挑战

x² - 40x -10 = 0
What is the sum of the solutions to the given equation?

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二次方程・零点与韦达定理挑战

x² + y + 7 = 7
20x +100 - y = 0
The solution to the given system of equations is (x , y ). What is the value of x ?

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二次方程・零点与韦达定理挑战

x - y =1
x + y = x²-3
Which ordered pair is a solution to the system of equations above?

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二次方程・零点与韦达定理挑战

2x² -2 = 2x + 3

Which of the following is a solution to the equation above?

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二次方程・零点与韦达定理进阶

x ²-40x -10=0What is the sum of the solutions to the given equation?

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